document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009370>Question 1009370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Admissions prices at a high school football game were $6 for adults and $2 for children. The total value of the tickets sold was $2528, and 454 tickets were sold. How many adult and how many child tickets were sold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625033 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the prices for adult and children's tickets, a and c.  Then we have<BR>\n" );
document.write( "a + c = 454  and the value equation is<BR>\n" );
document.write( "6a + 2c = 2528<BR>\n" );
document.write( "Let's double the first one and subtract from the second equation and get<BR>\n" );
document.write( "6a + 2c = 2528<BR>\n" );
document.write( "-(2a + 2c = 908)<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "4a = 1620<BR>\n" );
document.write( "a = 405 adult tix<BR>\n" );
document.write( "c = 49 children's tix </SPAN>\n" );
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