document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009549>Question 1009549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A formula for the surface area (A) of the rectangular solid is A=2lw+2lh+2wh where l represents length; w, width; and h, height. By doubling each of the dimensions (l, w, and h), the surface area will be multiplied by what factor? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625032 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I could give you the answer, but let's explore what happens if we substitute 2l, 2w, and 2h in for l, w, and h in the formula<BR>\n" );
document.write( "A = 2lw + 2lh + 2wh<BR>\n" );
document.write( "We get<BR>\n" );
document.write( "A' = 2(2l)(2w) + 2(2l)(2h) + 2(2w)(2h)<BR>\n" );
document.write( "A' = 8lw + 8lh + 8wh<BR>\n" );
document.write( "which is exactly FOUR times the original area A. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );