document.write( "Question 1789: A rectangular piece of sheet metal with an area of 1200 in^2 is to be bent into a cylindrical length (right circular cylinder) of stovepipe having a volume of 600 in^3. What are the dimensions of the sheet metal? \n" ); document.write( "
Algebra.Com's Answer #625 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
these sorts of questions are lovely questions (yes, i guess i must be a sad individual)...anyway, draw a rectangle, vertical side a and horizontal side b\r
\n" ); document.write( "\n" ); document.write( "the area = ab = 1200\r
\n" ); document.write( "\n" ); document.write( "Now draw an upright cylinder (by wrapping the length b into a circle)...its radius is length r, and its height is a\r
\n" ); document.write( "\n" ); document.write( "Volume of this cyclinder is the area of the circular end times the height...\r
\n" ); document.write( "\n" ); document.write( "\"volume+=+pi%2Ar%5E2%2Aa\"\r
\n" ); document.write( "\n" ); document.write( "now, seeing as how i do not know what r is, i had better find it. This is found from the circumference of the circle (which is the length b)...\r
\n" ); document.write( "\n" ); document.write( "circumference, b = \"2%2Api%2Ar\"\r
\n" ); document.write( "\n" ); document.write( "so, \"r+=+b%2F%282%2Api%29\"\r
\n" ); document.write( "\n" ); document.write( "So, we can get rid of the r in the volume equation..this is now re-written as:\r
\n" ); document.write( "\n" ); document.write( "\"volume+=+pi%2A+%28b%2F2%2Api%29%5E2+%2A+a\"
\n" ); document.write( "\"volume+=+%28pi%2Aa%2Ab%5E2%29%2F%284%2A%28pi%29%5E2%29\". This can be simplified to\r
\n" ); document.write( "\n" ); document.write( "\"volume+=+%28a%2Ab%5E2%29%2F%284%2Api%29\"\r
\n" ); document.write( "\n" ); document.write( "So we know the volume, but not a or b...2 unknowns in 1 equation is NOT good, so we need to get rid of either a or b...we do this by using the area equation, at the start of this explanation...let's re-write it as a = 1200/b\r
\n" ); document.write( "\n" ); document.write( "so we now get \"volume+=+%281200b%5E2%29%2F%284%2Ab%2Api%29\"\r
\n" ); document.write( "\n" ); document.write( "cancel the b with one of those in the \"b%5E2\" term, and simplifying the 1200 and 4 gives\r
\n" ); document.write( "\n" ); document.write( "\"volume+=+%28300b%29%2F%28pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"600+=+300b%2Fpi\"\r
\n" ); document.write( "\n" ); document.write( "so, \"b+=+%28600pi%29%2F%28300%29\" --> b=2pi\r
\n" ); document.write( "\n" ); document.write( "Substitute this into the area equation and you find a=600/pi. These are the dimensions of the sheet metal.\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon.
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