document.write( "Question 86339: Solve the following word problems. Be sure to show the equation you use for the solution.\r
\n" ); document.write( "\n" ); document.write( "Science and medicine. A bicyclist rode into the country for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?\r
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Algebra.Com's Answer #62496 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r=her rate (speed) going into the country
\n" ); document.write( "Then r+5=her speed in returning\r
\n" ); document.write( "\n" ); document.write( "Distance going=Distance returning\r
\n" ); document.write( "\n" ); document.write( "Distance going=rate going times time
\n" ); document.write( "Distance going=r*5
\n" ); document.write( "Distance returning=rate returning times time
\n" ); document.write( "Distance returning=(r+5)*4
\n" ); document.write( "So--
\n" ); document.write( "5r=4(r+5) get rid of parens
\n" ); document.write( "5r=4r+20 subtract 4r from both sides
\n" ); document.write( "5r-4r=4r-4r+20 collect like terms\r
\n" ); document.write( "\n" ); document.write( "r=20 mi/h---------------------speed going into the country\r
\n" ); document.write( "\n" ); document.write( "r+5=20+5=25 mi/h----------------speed returning\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "20*5=25*4\r
\n" ); document.write( "\n" ); document.write( "100=100\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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