document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009472>Question 1009472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in an examination, a student attempted 15 question correctly and secured 40 marks. if there were two types of question (2 marks and 4 marks), how many questions of 2 marks did he attempt correctly?solve </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624938 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be questions of 2 marks and let y be questions of 4 marks, then<BR>\n" );
document.write( "x + y = 15<BR>\n" );
document.write( "2x + 4y = 40<BR>\n" );
document.write( "solve first equation for y<BR>\n" );
document.write( "y = 15 - x<BR>\n" );
document.write( "substitute for y in second equation<BR>\n" );
document.write( "2x + 4(15-x) = 40<BR>\n" );
document.write( "2x + 60 - 4x = 40<BR>\n" );
document.write( "-2x = -20 <BR>\n" );
document.write( "x = 10<BR>\n" );
document.write( "there were 10 questions of 2 marks attempted correctly<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );