document.write( "Question 1009437: 476**0 is divisible by both 3 and 11. The non-zero digits
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Algebra.Com's Answer #624928 by Edwin McCravy(20065) $\"\"$ $\"About$

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476**0 is divisible by both 3 and 11. The non-zero digits
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document.write( "It has to be divisible by 10 because it ends in a 0\r\n" );
document.write( "It is divisible by 3 and 11, which are both prime, \r\n" );
document.write( "so it has to be divisible by 10*3*11 = 330.\r\n" );
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document.write( "The most it could be is 476990\r\n" );
document.write( "The least it could be is 476110, since the digits aren't 0.\r\n" );
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document.write( "476990/330 = 1445.424242...\r\n" );
document.write( "476110/330 = 1442.757575...\r\n" );
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document.write( "So the number divided by 330 is between those,\r\n" );
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document.write( "So the number divided by 330 is either 1443, 1444 or 1445\r\n" );
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document.write( "So the number is either \r\n" );
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document.write( "1443*330 = 476190\r\n" );
document.write( "1444*330 = 476520, or\r\n" );
document.write( "1445*330 = 476850\r\n" );
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document.write( "So there are three different possible answers,\r\n" );
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document.write( "476190, 476520, and 476850\r\n" );
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document.write( "Edwin

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