document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86383>Question 86383</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0495188891/algebrahomeworkh>Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 2/sqrt[3] + sqrt[2]<BR>\n" );
document.write( "Can you help me rationalize the denominator? I really apprecuate your help. It would help so much if you could show me how you do this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62491 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/sqrt[3] + sqrt[2]<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Multiply numerator and denominator by (sqrt3 - sqrt2) to get:<BR>\n" );
document.write( "[2(sqrt3 - sqrt2)]/[3-2]<BR>\n" );
document.write( "=2(sqrt3 - sqrt2)<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Why does this work?<BR>\n" );
document.write( "Because (sqrt3+sqrt2)(sqrt3-sqrt2) = 3+sqrt6-sqrt6-2 = 3-2=1<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );