document.write( "Question 1009366: In a mixture of milk and water, their ratio is 4:5 in the first container and the same mixture has 5:1 in the second container. In what ratio should the mixture be extracted from each container and poured into the third container so that the ratio of milk and water comes to 5:4 in the third container? \n" ); document.write( "
Algebra.Com's Answer #624874 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! This might be inconsistent with the intention of the exercise, but the ratios can be changed into percents of milk.\r \n" ); document.write( "\n" ); document.write( "First container, 44.44 percent \n" ); document.write( "Second container, 83.33333 percent \n" ); document.write( "WANTED, 55.56%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(or this could be done using ordinary fractions)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The units of measure are not given, but just assume any general units you want.\r \n" ); document.write( "\n" ); document.write( "x for first container to use , y for how much of the second container; \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "from the x value found, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find further that \n" ); document.write( "You could do the whole solution process using ordinary fractions, numerator denominator type, and get the same thing. \n" ); document.write( " |