document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009335>Question 1009335</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What must be added to x2^-7x to make it a perfect square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624850 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You take half the x-term coefficient and square it...thus from<BR>\n" );
document.write( "x^2 - 7x, we take half of -7 and get -3.5, then square it and get<BR>\n" );
document.write( "12.25<BR>\n" );
document.write( "so that x^2 - 7x + 12.25 = (x - 3.5)^2<BR>\n" );
document.write( "a perfect square... </SPAN>\n" );
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