document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009321>Question 1009321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two integers is 64. One integer is 20 less than twice the other. <BR>\n" );
document.write( "Find the smaller integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624833 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the integers x and y.  Then we have<BR>\n" );
document.write( "x + y = 64   and<BR>\n" );
document.write( "x = 2y - 20<BR>\n" );
document.write( "Substitute the second into the first equation and get<BR>\n" );
document.write( "2y - 20 + y = 64<BR>\n" );
document.write( "3y - 20 = 64<BR>\n" );
document.write( "3y = 84<BR>\n" );
document.write( "y = 28<BR>\n" );
document.write( "x = 36<BR>\n" );
document.write( "The smaller is 28. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );