document.write( "Question 1009299: Simplify
\n" ); document.write( "(sin^2x-tan^2x)/(tan^2xsin^2x)
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Algebra.Com's Answer #624823 by fractalier(6550) $\"\"$ $\"About$

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(sin^2x-tan^2x)/(tan^2xsin^2x) =
\n" ); document.write( "(sin^2x/(tan^2xsin^2x)) - (tan^2x)/(tan^2xsin^2x)) =
\n" ); document.write( "1/tan^2x - 1/sin^2x =
\n" ); document.write( "cos^2x/sin^2x - 1/sin^2x =
\n" ); document.write( "(cos^2x - 1)/sin^2x =
\n" ); document.write( "-sin^2x / sin^2x =
\n" ); document.write( "-1 \n" ); document.write( "

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