document.write( "Question 1009300: simplify
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Algebra.Com's Answer #624821 by fractalier(6550) $\"\"$ $\"About$

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From (tan^2x)/(1-sec^2x), multiply top and bottom by cos^2x and get
\n" ); document.write( "(tan^2x)(cos^2x)/(1-sec^2x)(cos^2x) =
\n" ); document.write( "sin^2x /(cos^2x - 1) =
\n" ); document.write( "sin^2x / -sin^2x =
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