document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008467>Question 1008467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jeb has five dollars worth of coins, but none of them are nickles or quarters. he has one half dollar. he has a total of one hundred coins. how many dimes and pennies does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624818 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of dimes and pennies, d and p.  Then we have<BR>\n" );
document.write( "d + p = 99 coins  and the values equation is<BR>\n" );
document.write( "10d + p = 450   (we work in cents)<BR>\n" );
document.write( "Now subtract these equations and get<BR>\n" );
document.write( "-9d = -351<BR>\n" );
document.write( "d = 39 dimes<BR>\n" );
document.write( "p = 60 pennies </SPAN>\n" );
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