document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008782>Question 1008782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thanks.. I think I did the wrong answer. <BR>\n" );
document.write( "Was.. Determine the sum of the sussesion <BR>\n" );
document.write( "An={3, 3/4, 3/16, 3/64...}  (3/4., 3/16... are fracctions...) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624817 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of this infinite series is found by<BR>\n" );
document.write( "S = a1 / (1-r)<BR>\n" );
document.write( "S = 3 / (1 - (1/4))<BR>\n" );
document.write( "S = 3 / (3/4) = 4 </SPAN>\n" );
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