document.write( "Question 1009305: how much 50% antifreeze solution and 40% antifreeze solution should be mixed to obtain 50 gallons of 47% antifreeze solution \n" ); document.write( "
Algebra.Com's Answer #624804 by fractalier(6550)\"\" \"About 
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Let x be the amount of 50% solutioin.
\n" ); document.write( "Thus 50-x will be the amount of 40% solution.
\n" ); document.write( "The set up is then
\n" ); document.write( ".50x + .40(50-x) = .47(50)
\n" ); document.write( ".50x + 20 - .40x = 23.5
\n" ); document.write( ".10x = 3.5
\n" ); document.write( "x = 35 gallons of 50% solution
\n" ); document.write( "50-x = 15 gallons of 40% solution
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