document.write( "Question 1008514: Twice the smallest of three consecutive odd integers is seven more than the largest. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #624798 by fractalier(6550) $\"\"$ $\"About$

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Call the three integers
\n" ); document.write( "x, x+2, and x+4 (since they are odd, you have to add two each time).
\n" ); document.write( "Then we have
\n" ); document.write( "2x = x+4 + 7
\n" ); document.write( "2x = x + 11
\n" ); document.write( "x = 11
\n" ); document.write( "The numbers are
\n" ); document.write( "11, 13, and 15 \n" ); document.write( "

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