document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009297>Question 1009297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An artist has been commissioned to make a stained glass window in the shape of a regular octagon. The octagon must fit inside an 18-in. square space. Determine the length of each side of the octagon. Round to the nearest hundredth of an inch </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624793 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the side of the octagon be x.<BR>\n" );
document.write( "If you draw the diagram of it, you will notice that<BR>\n" );
document.write( "x + x/sqrt(2) + x/sqrt(2) = 18<BR>\n" );
document.write( "since the sloping sides are hypotenuses of 45-45-90 right triangles.<BR>\n" );
document.write( "Factor out x and get<BR>\n" );
document.write( "x(1 + 2/sqrt(2)) = 18<BR>\n" );
document.write( "x(1 + sqrt(2)) = 18<BR>\n" );
document.write( "x = 18/(1+sqrt(2)) = 7.457 in </SPAN>\n" );
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