document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009185>Question 1009185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice of a large number equals 3 times smaller number and their sum is 40 find the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624786 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger number x and the smaller one y.  Then we have<BR>\n" );
document.write( "x + y = 40  and<BR>\n" );
document.write( "2x = 3y  or  x = (3/2)y<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "(3/2)y + y = 40<BR>\n" );
document.write( "(5/2)y = 40<BR>\n" );
document.write( "y = 16<BR>\n" );
document.write( "x = 24 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );