document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009283>Question 1009283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I pharmacists wishes to mix a solution that is 3% minoxidil . She has on hand 70 mL of a 1% solution and wishes to add some 5% solution to obtain the desired 3% solution how much 5% solution should she had </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624772 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount added, x.  The set up looks like this<BR>\n" );
document.write( "70(.01) + x(.05) = (70+x)(.03)<BR>\n" );
document.write( ".7 + .05x = 2.1 + .03x<BR>\n" );
document.write( "-1.4 = -.02x<BR>\n" );
document.write( "x = 1.4 / .02 = 70 mL<BR>\n" );
document.write( "Makes sense too...  </SPAN>\n" );
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