document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009270>Question 1009270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The answer and equation to how many liters of 80% acid solution must be mixed with a 20% acid solution to get 600 L of a 70% as a solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624765 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of 80% acid solution.<BR>\n" );
document.write( "Thus 600-x will be the amount of 20% acid.<BR>\n" );
document.write( "The set up is then<BR>\n" );
document.write( ".80x + .20(600-x) = .70(600)<BR>\n" );
document.write( ".80x + 120 - .20x = 420<BR>\n" );
document.write( ".6x = 300<BR>\n" );
document.write( "x = 500 L of 80% solution<BR>\n" );
document.write( "600-x = 100 L of 20% solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );