document.write( "Question 1009260: Solve this equation, one is simultaneous, one is linear\r
\n" ); document.write( "\n" ); document.write( "x^2 + y^2 = 9
\n" ); document.write( "x + y = 3
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Algebra.Com's Answer #624753 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"x%5E2+%2B+y%5E2+=+9\".....eq.1
\n" ); document.write( "\"x+%2B+y+=+3\".....eq.2
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\n" ); document.write( "\n" ); document.write( "start with\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+3\".....eq.2 and solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3-y\".........eq.2a\r
\n" ); document.write( "\n" ); document.write( "substitute it in eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"%283-y%29%5E2+%2B+y%5E2+=+9\".....eq.1 and solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"9-6y%2By%5E2+%2B+y%5E2+=+9\"\r
\n" ); document.write( "\n" ); document.write( "\"2y%5E2-6y%2B9++=+9\"\r
\n" ); document.write( "\n" ); document.write( "\"2y%5E2-6y=+9-9\"\r
\n" ); document.write( "\n" ); document.write( "\"2y%28y-3%29=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"2y=+0\"=>\"y=0\"
\n" ); document.write( "if \"%28y-3%29=+0\"=>\"y=3\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.2a, substitute \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3-y\".........eq.2a if \"y=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3-0\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+3-y\".........eq.2a if \"y=3\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3-3\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "so, we have two points of intersection of given lines and they are:\r
\n" ); document.write( "\n" ); document.write( "(\"3\",\"0\") and (\"0\",\"3\")\r
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