document.write( "Question 1009249: how do you solve log(base4)(4x+9)=1 \n" ); document.write( "

Algebra.Com's Answer #624743 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
It's a trick. Just express $\"+1+\"$ as a log.
\n" ); document.write( "In this case: $\"+1+=+log%28+4%2C4+%29+\"$
\n" ); document.write( " $\"+log%28+4%2C+%28+4x+%2B+9+%29%29+=+log%28+4%2C4+%29+\"$
\n" ); document.write( "Then it follows:
\n" ); document.write( " $\"+4x+%2B+9+=+4+\"$
\n" ); document.write( " $\"+4x+=+-5+\"$
\n" ); document.write( " $\"+x+=+-5%2F4+\"$
\n" ); document.write( "----------------
\n" ); document.write( "Plug this back into original equation
\n" ); document.write( " $\"+log%28+4%2C+%28+4x+%2B+9+%29%29+=+1+\"$
\n" ); document.write( " $\"+log%28+4%2C+%28+4%2A%28-5%2F4%29+%2B+9+%29%29+=+1+\"$
\n" ); document.write( " $\"+log%28+4%2C+4+%29+=+1+\"$
\n" ); document.write( " $\"+1+=+1+\"$
\n" ); document.write( "OK \n" ); document.write( "

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