document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008645>Question 1008645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ama's age is two - thirds that of her elder sister. Four  years ago ama's age was half the sisters.how old is the sister  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624734 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call Ama's age NOW, a.  Her sister's age NOW will be s.  Then we have<BR>\n" );
document.write( "a = (2/3)s<BR>\n" );
document.write( "a - 4 = (1/2)(s - 4)<BR>\n" );
document.write( "Substitute the first into the second equation and get<BR>\n" );
document.write( "(2/3)s - 4 = (1/2)(s - 4)<BR>\n" );
document.write( "Multiply by 6 to clear fractions and get<BR>\n" );
document.write( "4s - 24 = 3(s - 4)<BR>\n" );
document.write( "4s - 24 = 3s - 12<BR>\n" );
document.write( "Subtract 3s and add 24 and get<BR>\n" );
document.write( "s = 12<BR>\n" );
document.write( "a = (2/3)(12) = 8<BR>\n" );
document.write( "Ama is 8, the sister is 12. </SPAN>\n" );
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