document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009234>Question 1009234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One square has a side length that is 1 footgreater than that of a smaller square. If the combined area of the two squares is 113 feet. find the length of the side of the smaller square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624730 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the side of the smaller square, x.<BR>\n" );
document.write( "Thus the larger square has a side of x+1.<BR>\n" );
document.write( "Since area is side squared, we have<BR>\n" );
document.write( "x^2 + (x+1)^2 = 113<BR>\n" );
document.write( "x^2 + x^2 + 2x + 1 = 113<BR>\n" );
document.write( "2x^2 + 2x - 112 = 0<BR>\n" );
document.write( "x^2 + x - 56 = 0<BR>\n" );
document.write( "(x + 8)(x - 7) = 0<BR>\n" );
document.write( "X = -8  or  x = 7<BR>\n" );
document.write( "Can't be negative so you have a side of<BR>\n" );
document.write( "7 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );