document.write( "Question 1009159: Find three consecutive odd integers such that the product of the first and third is equal to 1 less than twice the second. \r
\n" ); document.write( "\n" ); document.write( "It's quite a confusing problem to read, but I wasn't taught this in class because I recently moved schools.
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Algebra.Com's Answer #624707 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Find three consecutive odd integers such that the product of the first and third is equal to 1 less than twice the second. \r
\n" ); document.write( "\n" ); document.write( "It's quite a confusing problem to read, but I wasn't taught this in class because I recently moved schools.
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Let the smallest be S
\n" ); document.write( "Then others are: S + 2, and S + 4
\n" ); document.write( "We then get: S(S + 4) = 2(S + 2) - 1
\n" ); document.write( "\"S%5E2+%2B+4S+=+2S+%2B+4+-+1\"
\n" ); document.write( "\"S%5E2+%2B+4S+-+2S+-+4+%2B+1+=+0\"
\n" ); document.write( "\"S%5E2+%2B+2S+-+3+=+0\"
\n" ); document.write( "(S + 3)(S - 1) = 0
\n" ); document.write( "S, or smallest = \"highlight_green%28-+3%29\" OR \"highlight_green%28S+=+1%29\"
\n" ); document.write( "You should be able to find the other 2 \n" ); document.write( "
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