document.write( "Question 1009151: Find the points of intersection, if any, of the pair of curves :
\n" ); document.write( "x^2+y^2=13 , y=x+1
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #624692 by ikleyn(52794) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "Find the points of intersection, if any, of the pair of curves :
\n" ); document.write( "x^2+y^2=13 , y=x+1
\n" ); document.write( "----------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "Substitute y from the second equation into the first one. In this way you exclude y and obtain single equation for variable x:\r\n" );
document.write( "\r\n" );
document.write( " +  = .\r\n" );
document.write( "\r\n" );
document.write( "Simplify and solve this quadratic equation:\r\n" );
document.write( "\r\n" );
document.write( " = ,\r\n" );
document.write( "\r\n" );
document.write( " = .\r\n" );
document.write( "\r\n" );
document.write( "The roots are  = -3 and  = 2.\r\n" );
document.write( "\r\n" );
document.write( "Hence, the pairs (x,y) = (-3,-2) and (2,3) are our intersection points.\r\n" );
document.write( "\r\n" );
document.write( "Answer. the pairs (x,y) = (-3,-2) and (2,3) are the two intersection points.\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );