document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009132>Question 1009132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find two consecutive even integers such that three times the first equals twice the second </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624676 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624676\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be some integer. The expression 2x represents any even integer. The next even integer after 2x is 2x+2\r<BR>\n" );
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document.write( "so we have\r<BR>\n" );
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document.write( "first even integer: 2x<BR>\n" );
document.write( "second even integer: 2x+2\r<BR>\n" );
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document.write( "the two even integers are as close as possible.\r<BR>\n" );
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document.write( "three times the first equals twice the second\r<BR>\n" );
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document.write( "3*(first) = 2*(second)\r<BR>\n" );
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document.write( "3*2x = 2*(2x+2)\r<BR>\n" );
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document.write( "6x = 4x + 4\r<BR>\n" );
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document.write( "6x - 4x = 4\r<BR>\n" );
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document.write( "2x = 4\r<BR>\n" );
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document.write( "x = 4/2\r<BR>\n" );
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document.write( "x = 2\r<BR>\n" );
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document.write( "If x = 2, then 2x = 2*2 = 4 and 2x+2 = 2*2+2 = 6\r<BR>\n" );
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document.write( "The two consecutive even integers are 4 and 6 </SPAN>\n" );
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