document.write( "Question 1009036: Prove the argument valid. Where = stands for a bi-conditional.\r
\n" ); document.write( "\n" ); document.write( "~(A & B) = ~C
\n" ); document.write( "(D v E) > C // E > A
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Algebra.Com's Answer #624646 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm going to use a conditional proof. So that means we assume E is true (line 3). If we can show it leads to A (line 12), then E > A is true.\r
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NumberStatementLines UsedReason
1~(A & B) = ~C
2(D v E) > C
.:E > A
3EACP
4E v D3Add
5D v E4Comm
6C2,5MP
7~~C6DN
8[~(A & B) > ~C] & [~C > ~(A & B)]1ME
9~(A & B) > ~C8Simp
10~~(A & B)9,7MT
11A & B10DN
12A11Simp
13E > A3-12CP
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\n" ); document.write( "\n" ); document.write( "Abbreviations/Acronyms Used:\r
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\n" ); document.write( "\n" ); document.write( "ACP = Assumption for Conditional Proof
\n" ); document.write( "Add = Addition
\n" ); document.write( "Comm = Commutation
\n" ); document.write( "CP = Conditional Proof
\n" ); document.write( "DN = Double Negation
\n" ); document.write( "ME = Material Equivalence
\n" ); document.write( "MP = Modus Ponens
\n" ); document.write( "MT = Modus Tollens
\n" ); document.write( "Simp = Simplification
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