document.write( "Question 1009099: Mike has 400 yards of net and wants to enclose a rectangular area.
\n" ); document.write( "1. Express area of A as a function of the width (w).
\n" ); document.write( "400=2(w+1)
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\n" ); document.write( "2. For what value of w is the area the largest?
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\n" ); document.write( "3. What is the maximum area?
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Algebra.Com's Answer #624640 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
w and L, the dimensions, and perimeter is \"2w%2B2L=400\". Simplify this!
\n" ); document.write( "\"w%2BL=200\".\r
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\n" ); document.write( "\n" ); document.write( "Area is wL, and naming area as a function, you may choose A.
\n" ); document.write( "\"A=wL\".\r
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\n" ); document.write( "\n" ); document.write( "You want to be more specific for which is the input variable for A. Look at the simplified perimeter equation.
\n" ); document.write( "Either \"w=200-L\" or \"L=200-w\". Choose one and work with it.\r
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\n" ); document.write( "\n" ); document.write( "One way, A as a function of w;
\n" ); document.write( "\"highlight%28A%28w%29=w%28200-w%29%29\";
\n" ); document.write( "and using this in this factored form will be convenient. This A(w) is a parabola with vertex as a maximum point. The vertex occurs in the exact middle of the roots or zeros, using w as the horizontal axis values.
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