document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008387>Question 1008387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular picture frame is 80 centimeter. Two times the width is equal to the length increased by five. Find its dimensions.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624585 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W = 80.  We also have<BR>\n" );
document.write( "2W = L + 5  or <BR>\n" );
document.write( "L = 2W - 5<BR>\n" );
document.write( "Now substitute this onto the first equation...we get<BR>\n" );
document.write( "2(2W - 5) + 2W = 80<BR>\n" );
document.write( "4W - 10 + 2W = 80<BR>\n" );
document.write( "6W - 10 = 80<BR>\n" );
document.write( "6W = 90<BR>\n" );
document.write( "W = 15 cm<BR>\n" );
document.write( "L = 2(15) - 2 = 25 cm </SPAN>\n" );
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