document.write( "Question 86361: Evaluate if a=-3 b= 3/4 c=-1/2\r
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document.write( "c-a / b-c
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document.write( "Divided = / -1/2-(-3)=c-a
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document.write( " 3/4-(-1/2)=b-c\r
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document.write( " -1/2+3=5/2
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document.write( " 3/4+1/2=5/4
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document.write( " 5/2/5/4 = 5/2.4/5
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document.write( " = 2 \n" );
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Algebra.Com's Answer #62458 by chitra(359)![]() ![]() You can put this solution on YOUR website! To evaluate the expression \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given the values \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "On substituting these values, we get: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Taking LCM, we get: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--> \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> 2 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Regards\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |