document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007933>Question 1007933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let a, b, and c represent real numbers that are not consecutive terms of an arithmetic sequence or of a geometric sequence. <BR>\n" );
document.write( "If a<b<c, determine a number that when added to a, b, and c yields consecutive terms of a geometric sequence. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624576 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's one possibility...let a, b, and c be 2, 5, and 9.<BR>\n" );
document.write( "Then add 7 to each and get<BR>\n" );
document.write( "9, 12, 16, a geometric sequence where the common ratio is 4/3.<BR>\n" );
document.write( "I solved this using this proportion:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B5%29%2F%28x%2B2%29+=+%28x%2B9%29%2F%28x%2B5%29 ALIGN=MIDDLE  ALT=\"%28x%2B5%29%2F%28x%2B2%29+=+%28x%2B9%29%2F%28x%2B5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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