document.write( "Question 1008812: 1.A police officer is investigating a crime which occurred in a rectangular field next to a building. He wants to seal the three sides of the area around the scene with 300 m of yellow police tape. What is the maximum area that he can enclose and what are the dimensions of this area? (Hint: Draw a picture and introduce a variable x for the width…think about an expression for the length in terms of x) (6 marks)\r
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Algebra.Com's Answer #624573 by ankor@dixie-net.com(22740)\"\" \"About 
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He wants to seal the three sides of the area around the scene with 300 m of yellow police tape.
\n" ); document.write( " What is the maximum area that he can enclose and what are the dimensions of this area?
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\n" ); document.write( "Let L = the length and x = the width of the rectangle
\n" ); document.write( "then because 3 sides are what is needed, therefore:
\n" ); document.write( "L + 2x = 300
\n" ); document.write( "L = (-2x+300), use this form for substitution
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\n" ); document.write( "Area = L * x
\n" ); document.write( "Replace L
\n" ); document.write( "A = x(-2x+300)
\n" ); document.write( "A = -2x^2 + 300x
\n" ); document.write( "Maximum area occurs at the axis of symmetry, x = -b/(2a)
\n" ); document.write( "x = \"%28-300%29%2F%282%2A-2%29\"
\n" ); document.write( "x = +75 is width
\n" ); document.write( "then
\n" ); document.write( "L = -2(75) + 300
\n" ); document.write( "L = 150 is the length
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\n" ); document.write( "Find the area: 150 * 75 = 11250 sq meters is max area
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