document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008954>Question 1008954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the exact value of the indicated trigonometric function of 0\r<BR>\n" );
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document.write( "sin 0=-4/7, tan 0 greater than 0 find sec 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624563 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the exact value of the indicated trigonometric function of 0 <BR>\n" );
document.write( "sin 0=-4/7, tan 0 greater than 0 find sec 0 <BR>\n" );
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document.write( "Note: If tan is positive and sin is negative, the angle is in QIII<BR>\n" );
document.write( "where x is negative and y is negative.<BR>\n" );
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document.write( "By definition, sin = y/r ; so y = -4 and r = 7<BR>\n" );
document.write( "Then x = -sqrt[7^2-4^2] = -sqrt[33]<BR>\n" );
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document.write( "Ans: sec(t) = r/x = -7/sqrt(33)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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