document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009009>Question 1009009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a certain rectangle is no more than 106 feet. If the length is eleven feet more than the width, what is the width?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624548 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624548\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W <= 106 and we also have<BR>\n" );
document.write( "L = W + 11...now substitute and get<BR>\n" );
document.write( "2(W + 11) + 2W <= 106<BR>\n" );
document.write( "2W + 22 + 2W <= 106<BR>\n" );
document.write( "4W + 22 <= 106<BR>\n" );
document.write( "4W <= 84<BR>\n" );
document.write( "W <= 21 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );