document.write( "Question 1009005: Convert the equation to polar form. (Use variables r and θ as needed.)
\n" ); document.write( "y = 2x^2 \n" ); document.write( "

Algebra.Com's Answer #624544 by fractalier(6550) $\"\"$ $\"About$

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For y = 2x^2, we use
\n" ); document.write( "y = r sin θ and
\n" ); document.write( "x = r cos θ to get
\n" ); document.write( "r sin θ = 2(r cos θ)^2
\n" ); document.write( "r sin θ = 2r^2(cos θ)^2
\n" ); document.write( "sin θ = 2r(cos θ)^2 so that
\n" ); document.write( "r = sin θ / 2(cos θ)^2
\n" ); document.write( "which can also be expressed in terms of tan and sec...
\n" ); document.write( "r = (1/2)sec θ tan θ \n" ); document.write( "

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