document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008905>Question 1008905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a lacrosse field is 10yd less than twice its width, and the perimeter is 340yd. The defensive area is 7/22 of the total field. Find the defensive area of the lacrosse field  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624529 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "W=width; L=length=2W-10yds; P=perimeter<BR>\n" );
document.write( ".<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "340yds=2((2W-10yds)+W)<BR>\n" );
document.write( "170yds=3W-10yds<BR>\n" );
document.write( "180yds=3W<BR>\n" );
document.write( "60yds=W<BR>\n" );
document.write( "L=2W-10yds=2(60yds)-10yds=110yds<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Total Area=LW=(110yds)(60yds)=6600 sq yds<BR>\n" );
document.write( "Defensive area=(7/22)(6600 sq yds)=2100 sq yds<BR>\n" );
document.write( ".<BR>\n" );
document.write( "ANSWER: The defensive area is 2100 square yards.  </SPAN>\n" );
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