document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008998>Question 1008998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Shelia leaves on a long trip driving at a steady rate of 40 miles per hour.  Her sister Allison leaves from the same location traveling to the same destination 2 hours later.  She drives at a steady rate of 60 miles per hour.  How long after Allison leaves home will she catch up to Shelia? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624526 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can solve this using reason more than equations...<BR>\n" );
document.write( "Sheila drives 80 miles in the two hours before Allison leaves...that is her head start.<BR>\n" );
document.write( "Allison then covers 20 miles more than Sheila each hour thereafter.<BR>\n" );
document.write( "It will take her 80/20 = 4 hours to catch up to her. </SPAN>\n" );
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