document.write( "Question 1008991: convert 8-8i into polar form with argument θ between 0 and 2π \n" ); document.write( "
Algebra.Com's Answer #624523 by ikleyn(52776)\"\" \"About 
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\n" ); document.write( "8 - 8i = 8*(1-i).\r
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\n" ); document.write( "\n" ); document.write( "1 - i has a polar angle \"theta\" = \"2pi+-+pi%2F4\" = \"7pi%2F4\" and the modulus of \"sqrt%282%29\".\r
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\n" ); document.write( "\n" ); document.write( "Therefore, 8-8i = \"8%2Asqrt%282%29%2A%28cos%287pi%2F4%29+%2B+i%2Asin%287pi%2F4%29%29\".\r
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