document.write( "Question 1008976: A person invests some money at 14%, with $8,000 more than this amount invested at 12%. The total annual income from the investments is $9,280.
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Algebra.Com's Answer #624512 by Boreal(15235)\"\" \"About 
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X=INVESTED AT 14%
\n" ); document.write( "X+8000=INVESTED AT 12%
\n" ); document.write( "INCOME=
\n" ); document.write( ".14X+(.12)(x+8000)=.14X+.12X+960=9280
\n" ); document.write( ".26X=8320
\n" ); document.write( "X=$32000 answer
\n" ); document.write( "X+$8000=$40000
\n" ); document.write( "INTEREST ON FIRST IS $4480
\n" ); document.write( "(.12)(x+8000)=$4800
\n" ); document.write( "CHECKS
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