document.write( "Question 1008967: a line parallel to the graph 2x + y = 5 thru (2,-3) \n" ); document.write( "
Algebra.Com's Answer #624496 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( " given:
\n" ); document.write( "\"2x+%2B+y+=+5\"
\n" ); document.write( "\"y+=+-2x%2B5\" \r
\n" ); document.write( "\n" ); document.write( "(\"2\",\"-3\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

\n" ); document.write( "
\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"-2\" (its from the slope of \"y=-2%2Ax%2B5\" which is also \"-2\").\n" ); document.write( "Also since the unknown line goes through (2,-3), we can find the equation by plugging in this info into the point-slope formula
\n" ); document.write( "
\n" ); document.write( " Point-Slope Formula:
\n" ); document.write( "
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y%2B3=-2%2A%28x-2%29\" Plug in \"m=-2\", \"x%5B1%5D=2\", and \"y%5B1%5D=-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y%2B3=-2%2Ax%2B%282%29%282%29\" Distribute \"-2\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y%2B3=-2%2Ax%2B4\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-2%2Ax%2B4-3\"Subtract \"-3\" from both sides to isolate y
\n" ); document.write( "
\n" ); document.write( " \"y=-2%2Ax%2B1\" Combine like terms
\n" ); document.write( "
\n" ); document.write( " So the equation of the line that is parallel to \"y=-2%2Ax%2B5\" and goes through (\"2\",\"-3\") is \"y=-2%2Ax%2B1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So here are the graphs of the equations \"y=-2%2Ax%2B5\" and \"y=-2%2Ax%2B1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=-2%2Ax%2B5\" (red) and graph of the line \"y=-2%2Ax%2B1\"(green) that is parallel to the given graph and goes through (\"2\",\"-3\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );