document.write( "Question 1008936: Could you please tell me what formula to use to solve this problem? A study found that the mean migration distance of the green turtle was 2200 kiloeters and the standard deviation was 625 kilometers. Assume that the distances are normally distributed. Seventy % of all the distances traveled were greater than how many kilometers? I would appreciate help with this one. \n" ); document.write( "
Algebra.Com's Answer #624462 by stanbon(75887)\"\" \"About 
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A study found that the mean migration distance of the green turtle was 2200 kiloeters and the standard deviation was 625 kilometers. Assume that the distances are normally distributed. Seventy % of all the distances traveled were greater than how many kilometers?
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\n" ); document.write( "Sketch a normal curve
\n" ); document.write( "Put 2200 km in the middle (it is the mean)
\n" ); document.write( "Keep in mind the std = 625 km.
\n" ); document.write( "The numbers to the right are greater than the numbers to the left.
\n" ); document.write( "Shade 70% of the area under the curve starting at the right end
\n" ); document.write( "and moving to the left.
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\n" ); document.write( "Find that left border value in ft.
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\n" ); document.write( "Since 70% is to the right of the border, 30% is to the left.
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\n" ); document.write( "Using a TI-84 calculator the z-value there is invNorm(0.30) = -0.5245
\n" ); document.write( "That means your border is 0.5245 stamdard deviations to the LEFT of the mean.
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\n" ); document.write( "Ans: 2200-0.5245*625 = 1872.25 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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