document.write( "Question 1008936: Could you please tell me what formula to use to solve this problem? A study found that the mean migration distance of the green turtle was 2200 kiloeters and the standard deviation was 625 kilometers. Assume that the distances are normally distributed. Seventy % of all the distances traveled were greater than how many kilometers? I would appreciate help with this one. \n" ); document.write( "
Algebra.Com's Answer #624462 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A study found that the mean migration distance of the green turtle was 2200 kiloeters and the standard deviation was 625 kilometers. Assume that the distances are normally distributed. Seventy % of all the distances traveled were greater than how many kilometers? \n" ); document.write( "------ \n" ); document.write( "Sketch a normal curve \n" ); document.write( "Put 2200 km in the middle (it is the mean) \n" ); document.write( "Keep in mind the std = 625 km. \n" ); document.write( "The numbers to the right are greater than the numbers to the left. \n" ); document.write( "Shade 70% of the area under the curve starting at the right end \n" ); document.write( "and moving to the left. \n" ); document.write( "--- \n" ); document.write( "Find that left border value in ft. \n" ); document.write( "--- \n" ); document.write( "Since 70% is to the right of the border, 30% is to the left. \n" ); document.write( "---- \n" ); document.write( "Using a TI-84 calculator the z-value there is invNorm(0.30) = -0.5245 \n" ); document.write( "That means your border is 0.5245 stamdard deviations to the LEFT of the mean. \n" ); document.write( "--- \n" ); document.write( "Ans: 2200-0.5245*625 = 1872.25 ft \n" ); document.write( "---------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------- \n" ); document.write( " |