document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008942>Question 1008942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 centimeters longer than the width of the rectangle. The perimeter of the<BR>\n" );
document.write( "rectangle is 88 centimeters. What is the area of the rectangle, in square centimeters?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624459 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W = 88<BR>\n" );
document.write( "We also have L = W + 4<BR>\n" );
document.write( "Now substitute this into the first equation and get<BR>\n" );
document.write( "2(W + 4) + 2W = 88<BR>\n" );
document.write( "2W + 8 + 2W = 88<BR>\n" );
document.write( "4W + 8 = 88<BR>\n" );
document.write( "4W = 80<BR>\n" );
document.write( "W = 20 cm<BR>\n" );
document.write( "L = 24 cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );