document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008904>Question 1008904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The site is rectangular with a permiter of 84m. Its length is 8m more than 4 times its width.\r<BR>\n" );
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document.write( "Work out the length and width of the rectangle you must present your answere with the corrct decimal place. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624451 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624451\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W = 84.  We also have<BR>\n" );
document.write( "L = 4W + 8<BR>\n" );
document.write( "Now substitute that into the first equation and get<BR>\n" );
document.write( "2(4W + 8) + 2W = 84<BR>\n" );
document.write( "8W + 16 + 2W = 84<BR>\n" );
document.write( "10W + 16 = 84<BR>\n" );
document.write( "10W = 68<BR>\n" );
document.write( "W = 6.8 m<BR>\n" );
document.write( "L = 4(6.8) + 8 = 35.2 m </SPAN>\n" );
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