document.write( "Question 1008903: Sorry I seem to be really bad at word problems and I can never get how to set them up and I always get thrown off I don't understand how to do this
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\n" ); document.write( "\n" ); document.write( "Landon can climb a certain hill at a rate that is 0.5mph slower than his rate coming down the hill. If it takes him 2 hours to climb the hill and 110 minutes to come down the hill, what is the rate coming down ? \n" ); document.write( "
Algebra.Com's Answer #624431 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate (r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "Let r=rate coming down hill
\n" ); document.write( "Then r-0.5=rate going up hill
\n" ); document.write( "We can't deal in both hours and minutes, sooo:
\n" ); document.write( "110 minutes =110/60 or 11/6 hours\r
\n" ); document.write( "\n" ); document.write( "Going up the hill:
\n" ); document.write( "d(up)=(r-0.5)*2
\n" ); document.write( "d(down)=r*(11/6)
\n" ); document.write( "We know that d(up)=d(down)
\n" ); document.write( "(r-0.5)*2=r*(11/6)
\n" ); document.write( "2r-1=11r/6 multiply each side by 6
\n" ); document.write( "12r-6=11r
\n" ); document.write( "12r-11r=6
\n" ); document.write( "r=6 mph
\n" ); document.write( "CK
\n" ); document.write( "d(up)=(6-0.5)*2=(5.5)*2=11 mi
\n" ); document.write( "d(down)=6*(11/6)=11 mi
\n" ); document.write( "Hope this helps---ptaylor\r
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