document.write( "Question 1008835: Tim drove halfway Indianapolis at 60 mi/h and the rest of the way at 80 mi/h. What was his average speed for the whole trip? \n" ); document.write( "
Algebra.Com's Answer #624414 by ikleyn(52776)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "Let L be the distance Tim covered.\r\n" );
document.write( "\r\n" );
document.write( "Since Tim drove half of the distance, \"L%2F2\", at the speed of 60 mph, he spent for it the amount of time \"L%2F2\"/\"60\" = \"L%2F%282%2A60%29\" hours.\r\n" );
document.write( "\r\n" );
document.write( "Since Tim drove the other half of the distance. \"L%2F2\", at the speed of 80 mph, he spent for it the amount of time \"L%2F2\"/\"80\" = \"L%2F%282%2A80%29\" hours.\r\n" );
document.write( "\r\n" );
document.write( "The average speed is the whole distance L divided by the time spent, which is \"L%2F%282%2A60%29\" + \"L%2F%282%2A80%29\", or \r\n" );
document.write( "\r\n" );
document.write( "\"L%2F%28L%2F%282%2A60%29+%2B+L%2F%282%2A80%29%29\" = \"%284%2A60%2A80%29%2F%282%2A60+%2B+2%2A80%29\" = \"2%2A60%2A80%29%2F%2860%2B80%29\" = 68.571 \"mi%2Fh\".\r\n" );
document.write( "\r\n" );
document.write( "The value \"2%2F%28%281%2Fu%29+%2B+%281%2Fv%29%29\" is called the harmonic mean of values u and v.\r\n" );
document.write( "\r\n" );
document.write( "Thus the average speed in this problem is the harmonic mean of the given speed 60 mph and 80 mph.\r\n" );
document.write( "\r\n" );
document.write( "See also the lesson Calculating an average speed: a train going from A to B and back in this site.\r\n" );
document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" );