document.write( "Question 1008876: three liters of alcohol water mixture contains 40% alcohol. how much alcohol must be evaporated and replaced by water in order to produce 30% alcohol mixture? \n" ); document.write( "
Algebra.Com's Answer #624404 by josgarithmetic(39618)\"\" \"About 
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v, the amount of alcohol to be removed and replaced with v volume of water. Note, the water
\n" ); document.write( "does not contribute any quantity of alcohol, being 0% alcohol. The volume of the solution
\n" ); document.write( "after evaporation and addition will still be the same 3 liters.\r
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\n" ); document.write( "\n" ); document.write( "Using fractions instead of percents,
\n" ); document.write( "\"%280.4%2A3-v%29%2F3=0.3\"
\n" ); document.write( "and understand the starting amount of alcohol was 0.4*3 LITERS, and v liters of alcohol
\n" ); document.write( "to remove is as 100% alcohol; the starting solution is 40% alcohol.\r
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\n" ); document.write( "\n" ); document.write( "Now, just solve for v.
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