document.write( "Question 86228: p squared+5p-5=0 \n" ); document.write( "
Algebra.Com's Answer #62435 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Lets solve this using the quadratic formula:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "the general form of the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"p%5E2%2B5%2Ap-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-5+%2B-+sqrt%28+%285%29%5E2-4%2A1%2A-5+%29%29%2F%282%2A1%29\" Plug in a=1, b=5, and c=-5\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-5+%2B-+sqrt%28+25-4%2A1%2A-5+%29%29%2F%282%2A1%29\" Square 5 to get 25\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-5+%2B-+sqrt%28+25%2B20+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-5%2A1\" to get \"20\"\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-5+%2B-+sqrt%28+45+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-5+%2B-+3%2Asqrt%285%29%29%2F%282%2A1%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-5+%2B-+3%2Asqrt%285%29%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-5+%2B+3%2Asqrt%285%29%29%2F2\" or \"p+=+%28-5+-+3%2Asqrt%285%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Which approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"p=0.854101966249685\" or \"p=-5.85410196624968\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"p=0.854101966249685\" or \"p=-5.85410196624968\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"p%5E2%2B5%2Ap-5\" we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on our calculator, we find that \"p=0.854101966249685\" and \"p=-5.85410196624968\".So this verifies our answer\r
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