document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008726>Question 1008726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a rectangle has perimeter of 840ft and a length that is 188 feet more than the width, what is the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624338 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W = 840  and we also have L = W + 188.  The substitute and we have<BR>\n" );
document.write( "2(W + 188) + 2W = 840<BR>\n" );
document.write( "2W + 376 + 2W = 840<BR>\n" );
document.write( "4W + 376 = 840<BR>\n" );
document.write( "4W = 464<BR>\n" );
document.write( "W = 116 feet<BR>\n" );
document.write( "L = W + 188 = 304 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );