document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008750>Question 1008750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this.. I did it but can solve it\r<BR>\n" );
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document.write( "Determine the first 4 susesion terms of:<BR>\n" );
document.write( "d=-3 and a1=7\r<BR>\n" );
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document.write( "Thanks for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624335 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a common difference of -3, we have<BR>\n" );
document.write( "a1 = 7<BR>\n" );
document.write( "a2 = 4<BR>\n" );
document.write( "a3 = 1<BR>\n" );
document.write( "a4 = -2<BR>\n" );
document.write( "a5 = -5<BR>\n" );
document.write( "and so on, decreasing by three each successive term... </SPAN>\n" );
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